114k views
1 vote
When trevor and brian play ping pong, the probability that trevor will win is 0.6. if trevor and brian play two games of ping pong, what is the probability that trevor wins the first game and brian wins the second game? assume games are independent?

User Ericslaw
by
7.8k points

1 Answer

7 votes

The probability that Trevor wins is
p=0.6 and the probability that Trevor loses is
q=1-p=1-0.6=0.4.

The probability that Brian wins is
0.4 (Trevor loses) and the probability that Brian loses is
0.6 (Trevor wins).

There are four different possibilities for 2 ping pong games:

  1. 1st and 2nd wins Trevor:
    Pr=0.6\cdot 0.6=0.36;
  2. 1st wins Trevor, 2nd wins Brian:
    Pr=0.6\cdot 0.4=0.24;
  3. 1st wins Brian, 2nd wins Trevor:
    Pr=0.4\cdot 0.6=0.24;
  4. 1st and 2nd wins Brian:
    Pr=0.4\cdot 0.4=0.16.

Check that in total
0.36+0.24+0.24+0.16=1.

Answer: the probability that Trevor wins the first game and Brian wins the second game is 0.24.

User Benjamin Netter
by
8.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories