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Find the limit. lim  θ→0  cos(4θ) − 1 / sin(7θ)

Can't figure this out. Any help is appreciated!

1 Answer

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The given limit is


\lim_(\theta ->0)(cos(4 \theta)-1)/(sin(7 \theta))

If we put 0 for theta , we will get 0/0 , which is not defined.

SO in this case we use L- Hospital's rule and differentiate both numerator and denominator. That is


\lim_(\theta ->0)((d/d \theta)(cos(4 \theta)-1))/((d / d \theta)(sin(7 \theta)))


\lim_(\theta ->0)(-4sin(4 \theta))/(7 cos(7 \theta))

Using substitution property of limit


(-4sin(4 *0))/(7 cos(7*0))


(-4*0)/(7 *1)=0

Therefore the value of the limit is 0.

User Luke Lowrey
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