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A certain shade of blue has a frequency of 7.35 × 1014 Hz. What is the energy of exactly one photon of this light?

User CathalMF
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2 Answers

3 votes

Solution:

According to the formula of energy we know that

E = hf, where h is Planck's constant,

6.63×10−34 J•s. This calculation is for one photon.

E = 4.873 * 10^ -19 J.

This is the required energy for one Photon.


User Starko
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3 votes

Energy of photon is equal to the product of Planck's constant (h) and frequency
\\u.

The mathematical expression is :


E=h\\u

where,

E = energy of photon

h = Planck's constant (
6.626* 10^(-34)Js)


\\u = frequency of light (
7.35 * 10^(14) Hz)

Plug in the values,


E=(6.626* 10^(-34)Js)* (7.35 * 10^(14) Hz)

=
48.7011 * 10^(-20) JsHz

Now, Hz = inverse of second

Energy of photon =
48.7011 * 10^(-20) J or
4.87011 * 10^(-19) J

Thus, energy of photon is equal to
4.87011 * 10^(-19) J




User Kajman
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