2 Answers

Starko · Answer 1 · 2019-07-04T15:45:40+0000

Solution:

According to the formula of energy we know that

E = hf, where h is Planck's constant,

6.63×10−34 J•s. This calculation is for one photon.

E = 4.873 * 10^ -19 J.

This is the required energy for one Photon.

Kajman · Answer 2 · 2019-07-09T04:18:58+0000

Energy of photon is equal to the product of Planck's constant (h) and frequency
$\\u$ .

The mathematical expression is :

$E=h\\u$

where,

E = energy of photon

h = Planck's constant (
6.626* 10^(-34)Js )

$\\u$ = frequency of light (
7.35 * 10^(14) Hz )

Plug in the values,

E=(6.626* 10^(-34)Js)* (7.35 * 10^(14) Hz)

=
48.7011 * 10^(-20) JsHz

Now, Hz = inverse of second

Energy of photon =
48.7011 * 10^(-20) J or
4.87011 * 10^(-19) J

Thus, energy of photon is equal to

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