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How much volume (in cm3) is gained by a person who gains 11.1 lbs of pure fat?

User Rockallite
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2 Answers

2 votes

Final answer:

The volume gained by a person who gains 11.1 lbs of pure fat is approximately 5594.373 cm³, using the density of body fat which is 0.9 g/cm³.

Step-by-step explanation:

The question pertains to the conversion of weight gain in pounds to the volume it would occupy if it's pure body fat. This is a physics calculation as it involves the concepts of density and volume. To determine the volume gained by gaining 11.1 lbs (pounds) of pure fat, we should consider that the density of body fat is approximately 0.9 g/cm³ (grams per cubic centimeter). Since there are 453.59237 grams in a pound, we would first convert 11.1 lbs to grams.

11.1 lbs x 453.59237 g/lb = 5034.93611 grams

Now, using the density of body fat, we can calculate the volume in cubic centimeters:

Volume = Mass / Density = 5034.93611 g / 0.9 g/cm³ = 5594.373456 cm³ (rounded to three decimal places).

Therefore, the volume gained by a person who gains 11.1 lbs of pure fat is approximately 5594.373 cm³.

User Gutompf
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6.1k points
5 votes

The density of human fat is
0.918 g/cm^(3). The mass of the pure fat is 11.1 lbs.

First convert mass from lb to g as follows:

1 lb=453.592 g

Thus,


11.1 lb\rightarrow 11.1* 453.592 g=5034.875 g

Density of a substance is defined as mass per unit volume, thus volume can be calculated as:


V=(m)/(d)

Putting the values,


V=(5034.875 g)/(0.918 g/cm^(3))=5484.61 cm^(3)

Therefore, volume gained by person will be
5484.61 cm^(3).

User NiklasMH
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5.5k points