Question

The mass of a molecule of penicillin is 10^-18 kilogram and the mass of a molecule of insulin is 10^-23 kilogram. How many times greater is the mass of a molecule of penicillin than the mass of a molecule of insulin?

Answer 1

`\frac{\text{mass of penicillin}}{\text{mass of insulin}}=(10^(-18)\,kg)/(10^(-23)\,kg)=10^(-18-(-23))=10^(5)`

The mass of a molecule of penicillin is 10⁵ times that of a molecule of insulin.

Answer 2

Answer:
`10^(5)` times

Explanation:

Given : The mass of a molecule of penicillin is
`10^-18` kilogram.

The mass of a molecule of insulin is
`10^-23` kilogram.

Now, the number of times the mass of a molecule of penicillin is greater than the mass of a molecule of insulin :-

`(10^(-18))/(10^(-23))`

Using law of exponent :

`(a^m)/(a^n)=a^(m-n)`

we have,

`(10^(-18))/(10^(-23))=10^(-18-(-23))=10^(-18+23)=10^(5)`

Hence, the mass of a molecule of penicillin is
`10^(5)` times greater than the mass of a molecule of insulin.