Question

A flea jumps straight up to a maximum height of 0.440 m . what is its initial velocity v0 as it leaves the ground?'

Answer 1

Initial velocity =
`\(v_0\)`

acceleration in the downward direction = -9.8
`\(\frac {m}{s^2}\)`

Final velocity at the highest point = 0

Maximum height reached = 0.440 m

Now, Using third equation of motion:

`\(v^2 = {v_0}^(2) + 2aH`

`\(0^2 = {v_0}^(2) - 2 * 9.8 * 0.440`

`\({v_0}^(2) = 2 * 9.8 * 0.440\)`

`\(v_0 = 2.936 \frac {m}{s}\)`

Velocity with which the flea jumps =
`\(2.936 \frac {m}{s}\)`