Distance between stations = 1180 m
We have v = u+at
When the train is accelerating v = 0+0.100*δt1 = 0.1δt1
When the train is decelerating 0 = 0.1δt1 - 0.350*δt2
So δt1 = 3.5 δt2
Now we have s = ut +
For the accelerating part
S1 = 0*δt1 +

For the decelerating part
S2 =

We have S1+S2 = 1180
