Question

The compound copper(ii) chloride is a strong electrolyte. write the reaction when solid copper(ii) chloride is put into water:

Answer 1

Answer: The chemical equation for the ionization of copper (II) chloride is written below.

Step-by-step explanation:

Strong electrolyte is defined as the electrolyte which dissociates completely into its ions when dissolved in water.

We are given:

Copper (II) chloride is a strong electrolyte and is formed by copper and chloride ions.

The chemical equation for the ionization of copper (II) chloride follows:

`CuCl_2(s)\rightarrow Cu^(2+)(aq.)+2Cl^-(aq.)`

By Stoichiometry of the reaction:

1 mole of solid copper (II) chloride produces 1 mole of copper ions and 2 moles of chloride ions

Hence, the chemical equation for the ionization of copper (II) chloride is written above.

Answer 2

Compounds which on dissolving in water, completely dissociates into its ions are strong electrolytes. Strong bases, strong acids and few salts are strong electrolytes. In solution, these ions are good conductor of electric current. Only ions and no molecules of electrolytes are present in the solution.

The given strong electrolyte is copper (II) chloride.

So, on putting copper (II) chloride in water it just dissolves and only its negative and positive ions will exist in the aqueous solution.

The reaction when solid copper(II) chloride is put into water is:

`CuCl_2+H_2O\rightarrow Cu^(2+)(aq)+2Cl^(-)(aq)`