Question

A lady bug walks 10 cm forward then 5 cm backwards in 20 seconds. what is the average speed of the ladybug ?

Answer 1

7.5 x 10^-3 ms^-1 OR 0.0075 m/s

Answer 2

The answer is average speed is equal to 0.25cm/sec

Step by step Explanation:

1-The average speed is defined as the relationship between the displacement that a body made and the total time it took to perform it.

2- The formula that allows to calculate the average velocity is
`V  = (ΔX)/(ΔT)` where (V) is the average speed, (ΔX) is the displacement and (ΔT) is the time interval.

3- As the ladybug advanced 10cm and moved back 5cm we have that the displacement is equal to 5cm, and the time interval is equal to 20 sec.

4- having this we can replace the problem data and find the average speed.

`v  = (5cm)/(20sec) \\v = 0.25(cm)/(sec)`