Question

If 4 dooms = 7 farzes, 1 bing = 2 wots, 2 zots = 3 dooms, and 9 farzes = 4 bings, then 3 zots = ? wots.

Answer 1

3 zots = 7 wots

3 zots × (3 dooms/2 zots) = ⁹/₂ dooms

⁹/₂ dooms × (7 farzes/4 dooms) = ⁶³/₈ farzes

⁶³/₈ farzes × (4 bings/9 farzes) = ⁷/₂ bings

⁷/₂ bings × (2 wots/1 bing) = 7 wots

Answer 2

Answer :
`3\text{ zots}=7\text{ wots}`

Explanation :

As we are given that:

4 dooms = 7 farzes

1 bing = 2 wots

2 zots = 3 dooms

9 farzes = 4 bings

Now we have to calculate 3 zots = ? wots.

We have to start from left hand side value (L.H.S).

`3\text{ zots}`

`2\text{ zots}=3\text{ dooms}`

`\text{ zots}=(3)/(2)\text{ dooms}`

`\Rightarrow 3* (3)/(2)\text{ dooms}`

`4\text{ dooms}=7\text{ farzes}`

`\text{ dooms}=(7)/(4)\text{ farzes}`

`\Rightarrow 3* (3)/(2)* (7)/(4)\text{ farzes}`

`9\text{ farzes}=4\text{ bings}`

`\text{ farzes}=(4)/(9)\text{ bings}`

`\Rightarrow 3* (3)/(2)* (7)/(4)* (4)/(9)\text{ bing}`

`1\text{ bings}=2\text{ wots}`

`\text{ bings}=(2)/(1)\text{ wots}`

`\Rightarrow 3* (3)/(2)* (7)/(4)* (4)/(9)* (2)/(1)\text{ wots}`

`\Rightarrow 7\text{ wots}`

Thus,
`3\text{ zots}=7\text{ wots}`