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Solve for y, y(a-b)=c(y+a)
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Solve for y, y(a-b)=c(y+a)

User Jeff Doolittle
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y(a-b)=c(y+a)\ \ \ \ \ |\text{use distributive property}\\\\ya-yb=cy+ca\ \ \ \ |-cy\\\\ay-by-cy=ac\\\\(a-b-c)y=ac\ \ \ \ \ |:(a-b-c)\\eq0\\\\\boxed{y=(ac)/(a-b-c)}

User YCalleecharan
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