131k views
3 votes
The coordinates of the midpoint of line GH are M(−132,−6) M ( − 13/2 , − 6 ) and the coordinates of one endpoint are G(−4, 1)

The coordinates of the other endpoint are ( , )

1 Answer

3 votes

Since, the coordinates of the midpoint of line GH are M
((-13)/(2), -6).

The coordinates of endpoint G are (-4,1)

We have to determine the coordinates of endpoint H.

The midpoint of the line segment joining the points
(x_1, y_1) and
(x_2, y_2) is given by the formula
((x_1+x_2)/(2),(y_1+y_2)/(2)).

Here, The endpoint G is (-4,1) So,
x_1 = -4 , y_1=1

Let the endpoint H be
(x_2,y_2)

The midpoint coordinate M is
((-13)/(2), -6).

So,
(-13)/(2) = (-4+x_2)/(2)


{-13} = {-4+x_2}


{-13}+4 = {x_2}


{x_2}=9

Now,
-6 = (1+y_2)/(2)


-12 = {1+y_2}


y_2= -13

So, the other endpoint H is (-9,-13).

User Anant Gupta
by
8.0k points