Question

Can someone help with these problems? please!

7+54÷3(2) and 24-4^2×3+15

Answer 1

PEMDAS is used for these kinds of problems so that you know what step to start with first.

P = Parentheses first

E = Exponents

M = Multiplication

D = Division

A = Addition

S = Subtraction

First Example:

Using the PEMDAS rule let's start with multiplication then divide then add.

`7+54/3(2) = 7+54/6=7+9=16`

Second Example:

Using the PEMDAS rule let's start with Exponents then multiplication then addition then subtraction.

`24-4^2*3+15=24-16*3+15=24-48+15=24-63=-39`

Hope this helps!

Answer 2

7+54-3(2)=43
24-4^2x3+15=-9