Question

Can someone please help

Answer 1

Acceleration of that planet is 30
`(m)/(s^(2) )`.

Given:

initial speed of hammer = 0
`(m)/(s)`

time = 1 s

distance = 15 m

To find:

Acceleration due to gravity = ?

Formula used:

Distance covered by hammer is given by,

s = ut +
`(1)/(2) a t^(2)`

s = distance

u = initial speed of hammer

t = time taken by hammer to reach ground

a = acceleration

Solution:

Distance covered by hammer is given by,

s = ut +
`(1)/(2) a t^(2)`

s = distance

u = initial speed of hammer

t = time taken by hammer to reach ground

a = acceleration

u = 0

t = 1 s

s = 15 m

a = g

Thus substituting these value in above equation.

15 = 0 +
`(1)/(2) g 1^(2)`

g = 15 × 2

g = 30
`(m)/(s^(2) )`

Thus, acceleration of that planet is 30
`(m)/(s^(2) )`.