Question

What are the excluded values for x for x+4/-3x^2+12x+36

Answer 1

C) -2, x=6

Explanation:

Answer 2

we are given

`((x+4))/(-3x^2+12x+36)`

we know that

values of x excluded when that value of x makes f(x) undefined

and any function is undefined when it's denominator becomes 0

so, we set denominator =0

and then we solve for x

`-3x^2+12x+36=0`

we can factor out

`-3(x^2-4x-12)=0`

`(x^2-4x-12)=0`

`(x-6)(x+2)=0`

we get

`(x-6)=0`

`x=6`

`(x+2)=0`

`x=-2`

so, excluded values are

`x=-2,x=6`..............Answer