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How many sulfur atoms are in 0.45 mol BaSO4??

2 Answers

4 votes


(0.45 mol BaSO_(4))*((6.022*10^23 molecules)/(mol))*((1 atom S)/(1 molecule BaSO_(4))) = 2.7*10^(23)

User Brian Carlton
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5 votes

Step-by-step explanation:

According to the mole concept, there are
6.022 * 10^(23) atoms present in one mole.

As it is given that number of moles of
BaSO_(4) are 0.45 mol.

Therefore, there is only one atom of sulfur. Hence, calculate atoms of sulfur as follows.


1 * 0.45 * 6.022 * 10^(23) atoms

=
2.709 * 10^(23) atoms

Thus, we can conclude that there are
2.709 * 10^(23) atoms of sulfur in 0.45 mol
BaSO_(4).

User Keith Coughtrey
by
8.1k points