Question

How many sulfur atoms are in 0.45 mol BaSO4??

Answer 1

`(0.45 mol BaSO_(4))*((6.022*10^23 molecules)/(mol))*((1 atom S)/(1 molecule BaSO_(4))) = 2.7*10^(23)`

Answer 2

Step-by-step explanation:

According to the mole concept, there are
`6.022 * 10^(23)` atoms present in one mole.

As it is given that number of moles of
`BaSO_(4)` are 0.45 mol.

Therefore, there is only one atom of sulfur. Hence, calculate atoms of sulfur as follows.

`1 * 0.45 * 6.022 * 10^(23)` atoms

=
`2.709 * 10^(23)` atoms

Thus, we can conclude that there are
`2.709 * 10^(23)` atoms of sulfur in 0.45 mol
`BaSO_(4)`.