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A key falls from a bridge that is 44 m above the water. It falls directly into a model boat, moving with constant velocity, that is 19 m from the point of impact when the key is released. What is the speed of the boat

User Msvcyc
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The time
t it takes for the key to fall 44 m is


44\,\mathrm m=\frac12\left(9.8\,(\mathrm m)/(\mathrm s^2)\right)t^2\implies t=3.0\,\mathrm s

(notice I'm taking the downward direction to be positive)

The boat, moving at a presumably constant speed, then has 3.0 s to travel 19 m to the point of impact, which means its speed must be


v=(19\,\mathrm m)/(3.0\,\mathrm s)=6.3\,(\mathrm m)/(\mathrm s)

User Tlink
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