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How many kilocalories are required to heat 100.00 g of water from 34.2°C to 96.5°C?

User Ctpenrose
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1 Answer

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Heat required in calories is given by product of mass in g and change in temperature in degree Celsius.

Formula is given by:


Q=m* \Delta T

where, Q = heat required in calories

m = mass of substance in g


\Delta T = change in temperature in degree Celsius

Insert the given vales of mass of water and temperature in above formula, we get:


\Delta T =
96.5^(o)C-34.2^(o)C

=
62.3 ^(o)C

Now,
Q=100 g* 62.3 ^(o)C

=
6230 calories

Thus, heat in kilocalories =
6.23 kilocalories



User Harsha Hulageri
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7.4k points