Question

How many liters of a 2% hydrochloric acid(HCI) solution and an 11% HCI solution should Karen mix to obtain 3 L of the 8% HCI solution needed in the chemistry lab?

Answer 1

Let x liters of a 2 % HCL is mixed with (3-x) liters of 11 % HCL solution to obtain 3 liters of 8% HCL solution. So the equation will be

`0.02x + 0.11(3-x)= 3*0.08`

Distributing 0.11 on 3-x, we will get

`0.02x +0.33 - 0.11x = 0.24`

Combining like terms

`-0.09x = -0.09`

Dividing both sides by -0.09

`x=1 liter`

So 1 liter of 2 % HCL solution is mixed with 2 liters of 11% HCl solution to get 3 liters of 8% HCL solution .