Question

To approach the runway, a small plane must begin at 9° descent starting from a height of 1,125 ft above the ground. How many feet from the runway is the airplane at the start of this approach? Round the distance to the nearest foot. 7192 ft 1139 ft 7103 ft 7191 ft

Answer 1

I just had this question and the correct answer is 7192ft

Answer 2

H = 7192 ft

Step-by-step explanation:

As we know that the angle of decent is 9 degree

and the the height of the plane from the ground is given as

H = 1125 ft

so here let say the distance is "d"

so we have

`(H)/(d) = sin\theta`

so we have

`d = (H)/(sin\theta)`

so we will have

`d = (1125)/(sin9)`

`d = 7192 ft`