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The density of silver is 10.5 g/cm3. A piece of silver with a mass of 101 g would occupy a volume of ________ cm3.

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Final answer:

A silver piece with a mass of 101 g and a density of 10.5 g/cm³ will occupy a volume of approximately 9.619 cm³.

Step-by-step explanation:

The density of silver is 10.5 g/cm³. To find the volume occupied by a piece of silver with a mass of 101 g, we can use the formula for density, which is:

Density = Mass / Volume

Rearranging the formula to solve for volume gives us:

Volume = Mass / Density

Substituting the given values, we get:

Volume = 101 g / 10.5 g/cm³

Volume = 9.619 cm³ (rounded to three decimal places).

Hence, a piece of silver with a mass of 101 g would occupy a volume of approximately 9.619 cm³.

User Utsav Dawn
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6.4k points
4 votes

i believe it is 1060.5

User LandonSchropp
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