Question

What is the wavelength of a 2.8 mhz ultrasound wave traveling through aluminum?

Answer 1

The wavelength of a 2.8 MHz ultrasound wave traveling through aluminum is approximately 1.82 mm.

Step-by-step explanation:

The wavelength of a wave can be calculated using the formula:

wavelength = wave speed / frequency

Given that the frequency of the ultrasound wave is 2.8 MHz (2.8 x 106 Hz) and the speed of sound in aluminum is about 5100 m/s, we can plug in these values:

wavelength = 5100 m/s / 2.8 x 106 Hz = 1.82143 x 10-3 meters = 1.82 mm

Answer 2

We use the relation between frequency, speed and wavelength as

`\lambda = (f)/(v)`.

Here,
`\lambda` is wavelength , f is frequency and v is speed.

Given
`f = 2.8 \ MHz` and we take the speed of sound in aluminium,
`v =  5100 \ m/s`.

Substituting these values in above relation, we get

`\lambda = (5100 \ m/s)/(2.8 \ MHz ) = (5100 \ m/s)/( 2.8 * 10 ^6 Hz) = 1821.43 * 10^(-6) m`

Thus , the wavelength of given ultrasound wave traveling through aluminum is
`1821.43 * 10^(-6) \ m = 0.001821 \ m = 1.82 \ mm`