Question

If a flea can jump straight up to a height of 0.410 m , what is its initial speed as it leaves the ground?

Answer 1

Initial velocity =
`\(v_0\)`

acceleration in the downward direction = -9.8
`\(\frac {m}{s^2}\)`

Final velocity at the highest point = 0

Maximum height reached = 0.410 m

Now, Using third equation of motion:

`\(v^2 = {v_0}^(2) + 2aH`

`\(0^2 = {v_0}^(2) - 2 * 9.8 * 0.410`

`\({v_0}^(2) = 2 * 9.8 * 0.410\)`

`\(v_0 = 2.834 \frac {m}{s}\)`

Speed with which the flea jumps =
`\(2.834 \frac {m}{s}\)`