speed of tortoise is given as v1 = 0.14 m/s
speed of hare is given as v2 = 20*0.14 = 2.8 m/s
now let say the total length of the path is "d"
so the total time taken by the tortoise to cover this
![t = (d)/(0.14)](https://img.qammunity.org/2019/formulas/physics/high-school/2joe99tr3dhd0pwnad348xktyyljjp9slh.png)
now given that hare took rest for 1 min
so total time of run for hare is (t - 60)s
so the distance that hare covered is given by
![d - 0.30 = 2.8 * (t - 60)](https://img.qammunity.org/2019/formulas/physics/high-school/wrsbjx8j7vl2bcb0bpaqkjxs5rjnxj5nnz.png)
now by above two equations
![d - 0.30 = 2.8 * (d)/(0.14) - 168](https://img.qammunity.org/2019/formulas/physics/high-school/m3ejlcu2q6hb2wewqret8m9h5hwrvosajn.png)
![168 - 0.30 = (20 - 1)d](https://img.qammunity.org/2019/formulas/physics/high-school/5ily87976j9we5a18lhdizk12btowqpgsb.png)
![d = 8.82 m](https://img.qammunity.org/2019/formulas/physics/high-school/rl82m5u7idtk5tgjnzmz6t25mb4as8p8wg.png)
and the time t is given by
![t = (8.82)/(0.14)](https://img.qammunity.org/2019/formulas/physics/high-school/rpcmyh4zufwsvuvfaj17hbmq3rxvkxyswq.png)
![t = 63 s](https://img.qammunity.org/2019/formulas/physics/high-school/s7pwyx9qoqkfgpb2b0p5wn3xnne14tq1d1.png)
so part a)
t = 63 s
part b)
d = 8.82 m