Question

A baseball player hit 62 home runs in a season. Of the 62 home​ runs, 24 went to right​ field, 17 went to right center​ field, 9 went to center​ field, 10 went to left center​ field, and 2 went to left field.

​(a)
What is the probability that a randomly selected home run was hit to right​ field?
​(b)
What is the probability that a randomly selected home run was hit to left​ field?
​(c)
Was it unusual for this player to hit a home run to left​ field? Explain.

Answer 1

Step-by-step explanation

Total home runs = 62

Right field = 24 , Right center field = 17, Center field = 9 , Left center field = 10 and Left field = 2

(a) The probability that a randomly selected home run was hit to right​ field = (Number of right field / Total home runs) =
`(24)/(62) = 0.3870...`

(b) The probability that a randomly selected home run was hit to left​ field = (Number of left field / Total home runs) =
`(2)/(62)= 0.0322...`

(c) As the probability that a home run was hit to the left field is 0.0322... or 3.22...% , that means there is very low chance for hitting to the left field. So, it was unusual for this player to hit a home run to left​ field.