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28 votes
28 votes
The second side of a triangular deck is 3 feet longer than the shortest​ side, and the third side is 3 feet shorter than twice the length of the shortest side. If the perimeter of the deck is 60 ​feet, what are the lengths of the three​ sides?

User Redben
by
2.7k points

1 Answer

29 votes
29 votes

Answer:

Side lengths are 15 ft, 18 ft, 27 ft

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Step-by-step explanation:

x = shortest side

x+3 = second side, which is 3 ft longer

2x-3 = third side

Add up those three expressions and set the result equal to 60, which is the stated perimeter. Solve for x.

(shortest side) + (second side) + (third side) = perimeter

(x) + (x+3) + (2x-3) = 60

4x = 60

x = 60/4

x = 15

The shortest side is 15 feet long.

x+3 = 15+3 = 18 feet is the second side

2x-3 = 2*15-3 = 30-3 = 27 feet is the third side, aka longest side.

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As a check,

15+18+27 = 60

which confirms our answers.

User Amos Folarin
by
3.1k points
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