We have been given that Wilma bought 4 boxes of Crunch-a-lot cereal.
Further, we know that one out of every 5 boxes has a coupon for a free box of Crunch-a-Lot. We need to figure out the probability that Wilma got 2 coupons?
This question is based on Bernoulli's Trials. We know that probability for r successful draws out of n trials is given by:
![_(r)^(n)\textrm{C}(p)^(r)(1-p)^(n-r)](https://img.qammunity.org/2019/formulas/mathematics/college/8j8ff2s0v05vgyphr64zo5jnirl428jt8i.png)
We have
. Upon substituting these values in this formula, we get:
![_(2)^(4)\textrm{C}((1)/(5))^(2)(1-(1)/(5))^(4-2)\\ \\ 6* ((1)/(5))^(2)((4)/(5))^(2)\\ \\ 6* (1)/(25)* (16)/(25)\\ \\ (96)/(625)\approx 0.1536](https://img.qammunity.org/2019/formulas/mathematics/college/tso73tsgcywn1l9qrrjqz6c9mamajcq7um.png)
This is the required probability.