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Wilma bought 4 boxes of Crunch-a-lot cereal. One out of every 5 boxes has a coupon for a free box of Crunch-a-Lot. What is the probability that Wilma got 2 coupons?

User Thegaram
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We have been given that Wilma bought 4 boxes of Crunch-a-lot cereal.

Further, we know that one out of every 5 boxes has a coupon for a free box of Crunch-a-Lot. We need to figure out the probability that Wilma got 2 coupons?

This question is based on Bernoulli's Trials. We know that probability for r successful draws out of n trials is given by:


_(r)^(n)\textrm{C}(p)^(r)(1-p)^(n-r)

We have
p=(1)/(5),n=4,r=2. Upon substituting these values in this formula, we get:


_(2)^(4)\textrm{C}((1)/(5))^(2)(1-(1)/(5))^(4-2)\\ \\ 6* ((1)/(5))^(2)((4)/(5))^(2)\\ \\ 6* (1)/(25)* (16)/(25)\\ \\ (96)/(625)\approx 0.1536

This is the required probability.


User Boris Strandjev
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