Answer:
In this system of equations, x is equal to one, and y is equal to three.
Explanation:
We can solve this by rearranging either equation to define either x or y, and plugging that into the other. As it happens, the first equation is conveniently arranged to define x, so let's use that:
3y + x = 10
3y + (2y - 5) = 10
5y - 5 = 10
y - 1 = 2
y = 3
Now that we know the value of y, we can plug it in to either of the original equations to find x:
x = 2y - 5
x = 2(3) - 5
x = 6 - 5
x = 1
Now we can check that our answer is correct by plugging that x value into either of the original equations:
3y + x = 10
3y + 1 = 10
3y = 9
y = 3
And because that gives us our original y value, we know that our answer is correct.