Question

In the diagram m angle ACB = 61
Find m angle BCD

Answer 1

Explanation:

In the given diagram,

m(∠ACB) + m(∠ACf) +m(∠FCE) = 180°

[Angles formed at point on a straight line]

It is given that m(∠ACB) = 61°

m(∠ACF) = 90°

Therefore, 61° + 90° + m(∠FCE) = 180°

151 + m(∠FCE) = 180

m(∠FCE) = 180 - 151

= 29°

Since m(∠FCE) = (∠BCD)

[vertical opposite angles]

Therefore, m(∠BCD) = 29°

Answer 2

we are given that

angle(ACF)=90

angle(ACB)=61

sum of all angles along any line is 180

so, we get

angle(ACF)+angle(ACD)=180

we can plug value

90+angle(ACD)=180

angle(ACD)=90

now, we can use formula

angle(ACD)=angle(ACB)+angle(BCD)

now, we can plug values

and we get

90=61+angle(BCD)

90-61=61-61+angle(BCD)

angle(BCD)=29................Answer