Question

At a veterinarian's office, 2 cats and 4 dogs are seen in a random order. What is the probability that the 2 cats are seen in a row?

Answer 1

`\bf\implies \textbf{Required Probability = }(1)/(3)`

Explanation:

Number of cats at veterinarian office = 2

Number of dogs at veterinarian office = 4

Total number of pets at veterinarian office = 2 + 4 = 6

Now, we need to find probability that 2 cats are seen in a row

⇒ No dog is seen between two cats

So, to find the required probability :

No. of favorable outcomes = 2

Total number of outcomes = 6

`\text{Hence, Probability = }\frac{\text{No. of favorable outcomes}}{\text{Total no. of otcomes}}\\\\\implies Probability = (2)/(6)\\\\\bf\implies \textbf{Required Probability = }(1)/(3)`