Question

Triangle ABC is translated on the coordinate plane below to create triangle A'B'C':

Triangle ABC, triangle A prime B prime C prime, and parallelogram EFGH on the coordinate plane with ordered pairs at A negative

If parallelogram EFGH is translated according to the same rule that translated triangle ABC, what is the ordered pair of point H'? (4 points)



(−3, −3)
(4, 9)
(7, 6)
(0, −5)

Answer 1

To find the coordinates of point H' after a translation, first determine the translation rule used on Triangle ABC to get Triangle A'B'C', then apply that rule to the coordinates of point H.

Step-by-step explanation:

The question you've presented involves finding the coordinates of point H' after applying the same translation that was used on Triangle ABC to create Triangle A'B'C'. To solve this, you would first need to determine the rule of translation by comparing the coordinates of any of the corresponding points in Triangle ABC and Triangle A'B'C'. Once the translation rule is established (for example, moving x units to the right/left and y units up/down), you would apply this same rule to the coordinates of point H in parallelogram EFGH to find the coordinates of point H'.

Answer 2

Your answer is (1, -7) What u do: label out the triangles points: A(-7, 6), B(-5, 3), C(-1, 3) to A'(1, 4), B'(3, 1), C'(7, 1)A to A' which is -7 to 1 is a 8 point difference and A to A' which is 6 to 4 is a -2 point difference, indicating: (x + 8, y - 2) B(-5, 3) -> (-5 + 8, 3 - 2) = B'(3, 1) C(-1, 3) -> (-1 + 8, 3 - 2) = C'(7, 1)Now to simply solve for H to H': We know H 's coordinates are: (-7, -5) Now add in the rule and solve: Now add in the rule and solve: (-7 + 8, -5 - 2) = 1,-7 Hope this helps :)