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Solve q.8 plzzzzzzzźzzzzzzzzzzz

Solve q.8 plzzzzzzzźzzzzzzzzzzz-example-1
User Jim Leask
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1 Answer

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hey!!

The given question should be as follows:-


(cosecA-sinA) (secA-cosA) = 1/(tanA+cotA).


L.H.S.


=(cosecA-sinA) (secA-cosA).


=(1/sinA-sinA)(1/cosA-cosA).


=(1-sin^2A) (1-cos^2A)/sinA.cosA.


=cos^2A.sin^2A/sinA.còsA.


=sinA.cosA/1.


=sinA.cosA/(sin^2A+cos^2A).


On dividing above and below by sinA.cosA.


=(sinA.cosA/sinA.cosA)/(sin^2A/sinA.cosA+cos^2A/sinA.cosA).


= 1/(tanA+cotA).

Hope it is clear and hope it would help you!

User Atamyrat Babayev
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