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9 times the sum of b and 2 is 8

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I suppose you want to solve the following equation for b:


9(b+2)=8

First of all, you need to divide both sides by 9:


b+2 = (8)/(9)

Then, subtract 2 from both sides:


b = (8)/(9)-2 = (8)/(9)-(18)/(9) = -(10)/(9)

User MiffTheFox
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