The first integer is 2n + 1,
the second integer is the previous one plus 2, which is (2n+1)+2 = 2n+3
the third integer is 2n + 5
the fourth integer is 2n + 7
so the sum of all...
(2n+1) + (2n+3) + (2n+5) + (2n+7) = 8n + 16
and this sum is equal to 44...
8n + 16 = 44 ... 8n = 28... n = 7/2
First integer is 2(7/2) + 1 = 8
so the integers are 8, 10, 12, 14