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Find the x and y intercepts of y = 2x^3 - 4x^2 algebraically

User Mushfiq
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1 Answer

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The x-intercept is the place where y = 0 and the y-intercept is the point where x = 0. Using this information, we can substitute 0 in for x and y to find the intercepts.


x-intercepts (where y = 0):


2x^3 - 4x^2 = 0


x^2(2x - 4) = 0

Here we can apply the Zero Product Property to find
x^2 = 0 and
2x - 4 = 0 separately.


x^2 = 0


x = 0

AND


2x - 4 = 0


2x = 4


x = 2

The x-intercepts are located at (0, 0) and (2, 0).


y-intercept (where x = 0):


y = 2(0)^3 - 4(0)^2


y = 0

The y-intercept is located at (0, 0).

User Cullimorer
by
9.0k points

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