Question

a lady bug walks 10 cm forward then 5 cm backwards in 20 seconds. what is the average speed of the ladybug ?

Answer 1

The average speed of the ladybug is 0.25 cm/s.

Step-by-step explanation:

The average speed of the ladybug can be calculated by dividing the total distance traveled by the total time taken. In this case, the ladybug walks 10 cm forward and then 5 cm backwards, resulting in a net displacement of 5 cm. Since the total time taken is 20 seconds, the average speed can be calculated as:

Average Speed = (Total Distance)/(Total Time) = 5 cm / 20 s = 0.25 cm/s

Therefore, the average speed of the ladybug is 0.25 cm/s.

Answer 2

A lady bug moves 10 cm forward and 5 cm backwards

so total distance moved by lady bug = 10 + 5 = 15 cm

total time taken by the lady bug

t = 20 s

so the average speed is given as

`v = (d)/(t)`

`v = (15)/(20)`

`v = 0.75 cm/s`

so its average speed is 0.75 cm/s