Final answer:
A woman who is heterozygous for the colorblindness gene will not be colorblind but will be a carrier of the trait. If she marries a man with normal color vision, there is a 50% chance that their son will be colorblind.
Step-by-step explanation:
Colorblindness is caused by a recessive x-linked gene. A woman who is heterozygous for this trait marries a man with normal color vision. If the woman is heterozygous, that means she carries one normal gene for color vision and one gene for colorblindness. Since colorblindness is recessive, the dominant normal gene will mask the recessive colorblind gene and the woman will not be colorblind. However, she will be a carrier of the colorblindness trait, which means she can pass it on to her children.
If the woman and the man have a son, he will have a 50% chance of being colorblind. This is because boys only have one X chromosome, and if they receive the colorblind gene from their mother, they will be colorblind. On the other hand, if the couple has a daughter, she will not be colorblind. This is because girls have two X chromosomes, and even if she receives the colorblind gene from her mother, she will also receive a normal gene from her father, which will mask the recessive colorblind gene.