3! x 3! x 4! x 1!
= (3 x 2 x 1) x (3 x 2 x 1) x (4 x 3 x 2 x 1) x (1)
= 4 x 3³ x 2³
= 4 x 27 x 8
= 32 x 27
= 864
Answer: 864 possible outcomes
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