Question

Angelina leaves her house walking at a speed of 20 meters per minute. Her sister walks behind her 15 minutes later at a speed of 25 meters per minute. After how many minutes has Angelina’s sister caught up to her?

Answer 1

So basically, you have to make two separate equations for the speed of each girl.

Angelina would be 20m + 20(15), with m being the minutes she has traveled.

Angelina's sister would be 25m, since she doesn't have the starting advantage that Angelina has.

So you would have to make them equal to each other to see what the value of m should be so that the girls have traveled the same distance (when Angelina's sister catches up to Angelina). So I'll then solve the equation.

20m + 20(15) = 25m

20(15) = 5m subtract 20m from each side

300 = 5m simplify the 20(15)

60 = m divide both sides by 5

So Angelina's sister will have caught up to her after 60 minutes.

Hope this helps!

Answer 2

Anglena's sister will caught up to her in 60 minutes.

Explanation:

equation of Angelina's walk can be described as

20m + 20(15),

whee m are the total minutes she has traveled.

Angelina's sister will be 25m, because

she doesn't have the starting advantage that Angelina has.

we will make them equal to each other to see what the value of m should be so that both of them have traveled the same distance (when Angelina's sister catches up to Angelina).

20m + 20(15) = 25m

20(15) = 5m subtracting 20m from both sides

300 = 5m multiplying the 20(15)

m=
`(300)/(5)`

m=60 minutes

Answer

Angelina's sister will have caught up to her after 60 minutes.