Question

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

What are the solutions to the equation?

x2 (4x − 3) (5x − 1) = 0

Answer 1

Hi!

x = 0

or

x = 1/5

or

x = 3/4

---

The process:

Step 1: Factor left side of equation.

Step 2: Set factors equal to 0.

-

Hope this helped :)

Answer 2

`x^2(4x-3)(5x-1)=0\iff x^2=0\ \vee\ 4x-3=0\ \vee\ 5x-1=0\\\\x^2=0\to\boxed{x=0}\\\\4x-3=0\ \ \ |+3\\4x=3\ \ \ |:4\\\boxed{x=(3)/(4)}\\\\5x-1=0\ \ \ |+1\\5x=1\ \ \ |:5\\\boxed{x=(1)/(5)}\\\\Answer:\ x=0\ or\ x=(3)/(4)\ or\ x=(1)/(5)`