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In a set of four consecutive positive integers, the smallest integer is less than half the largest integer. what is the largest integer that could be in the set?

2 Answers

2 votes

Answer:

5

Explanation:

Let the integers be n, n + 1, n + 2, and n + 3. We have

n < 1/2(n+3),

so 2n < n + 3. Subtracting n from both sides yields n < 3. Thus n is at most 2, and hence the largest integer, n + 3, is at most 2 + 3 = 5.

User Trent Earl
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3 votes

Let integers be x, x+1, x+2 and x+3

x < 0.5(x + 3)

x < 0.5x + 1.5

0.5x < 1.5

x < 3

so x = 2 given that they are positive integers

so the largest integer that could be in the set is 2 + 3 = 5 answer

User Gaurav Pandvia
by
8.1k points

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