Question

The distance around a standard tennis court is 228 feet. if the length of the court is 6 feet more than twice the width, find the dimensions of the tennis court.

Answer 1

Length (L): 2w + 6

width (w): w

Perimeter (P) = 2L + 2w

228 = 2(2w + 6) + 2(w)

228 = 4w + 12 + 2w

228 = 6w + 12

216 = 6w

36 = w

Length (L): 2w + 6 = 2(36) + 6 = 72 + 6 = 78

Answer: width=36 ft, length = 78 ft