Question

The distance between the centers of two atoms in a diatomic molecule is 1.22 angstroms. (an angstrom is 10-10 m.) calculate the distance in feet.

Answer 1

The distance between the centers of two atoms in a diatomic molecule is 1.22 angstroms, which converts to 4.00 × 10^-10 feet when using the conversion of 1 Å being equal to 1 × 10^-10 meters and knowing that 1 foot equals 0.3048 meters.

Step-by-step explanation:

The student has asked to calculate the distance in feet of the space between the centers of two atoms in a diatomic molecule, which is given as 1.22 angstroms.

To convert the distance from angstroms to feet, we first convert angstroms to meters and then from meters to feet. There are 1 ×10-10 meters in an angstrom, and 1 foot is equal to 0.3048 meters.

First, we convert 1.22 angstroms to meters:

1.22 Å × (1 × 10-10 meters/Å) = 1.22 × 10-10 meters

Now, we convert meters to feet:

1.22 × 10-10 meters × (1 foot / 0.3048 meters) = 4.00 × 10-10 feet

Therefore, the distance between the centers of the two atoms in the molecule is 4.00 × 10-10 feet.

Answer 2

In diatomic molecule, the distance between the centers of two atoms is 1.22
`\AA`.

Converting
`\AA` to m:

Since, 1
`\AA`=
`10^(-10) m`

Thus,

1.22
`\AA`=
`1.22* 10^(-10) m`

Now, Converting m to feet:

1 m=3.28 feet

Thus,

`1.22* 10^(-10) m=1.22* 10^(-10)* 3.28 feet=4* 10^(-10)feet`

Therefore, distance in feet is
`4* 10^(-10)`