Question

Algebra question please help

Answer 1

(square root of x)^2 < (5)^2

x<25

Answer 2

First, determine the domain: x ≥ 0 (because you can't square root a negative)

Next, square both sides of the equation and solve for "x".

(√x)² < (5)²

+/- x < 25

+x < 25 -x < 25

x< 25 x > -25 ⇒ Remember the domain is x ≥ 0

x < 25 and x ≥ 0 ⇒ 0 ≤ x

Answer: 0 ≤ x < 25 interval notation [0, 25)