- Zero Product Property: if a × b = 0, then either a or b = 0 or both a and b = 0.
(Make sure to set f(x) to zero)
So for this equation, I will be factoring by grouping. Firstly, what two terms have a product of -5x^2 and a sum of 4x? That would be 5x and -x. Replace 4x with 5x - x:
![0=5x^2+5x-x-1](https://img.qammunity.org/2019/formulas/mathematics/middle-school/6vaqkxlku0zk7hlmmd8m7rw815o7ou2phh.png)
Next, factor 5x^2 + 5x and -x - 1 separately. Make sure that they have the same quantity on the inside:
![0=5x(x+1)-1(x+1)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/mha7iu2m8ebpdabt8i5s46nn1tqlqxv36w.png)
Now you can rewrite the equation as:
![0=(5x-1)(x+1)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/szk33unx25ozukfprgctt952sf9hhj2spn.png)
Now apply zero product property to the factors to solve for x:
![5x-1=0\\5x=1\\x=(1)/(5)\\\\x+1=0\\x=-1](https://img.qammunity.org/2019/formulas/mathematics/middle-school/erbgvcgn67cp4t57mfpd0p787cym36y8te.png)
The x-intercepts are (1/5 ,0) and (-1,0).