Question

Complete the equation of the line through (-8,-2)(-4,6)

Answer 1

`\bf (\stackrel{x_1}{-8}~,~\stackrel{y_1}{-2})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-(-2)}{-4-(-8)}\implies \cfrac{6+2}{-4+8}\implies \cfrac{8}{4}\implies 2 \\\\\\ \begin{array} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-2)=2[x-(-8)]\implies y+2=2(x+8) \\\\\\ y+2=2x+16\implies y=2x+14`