Question

Devise a temperature scale, abbreviated g, for which the magnitude of the ideal gas constant is 1.00 j g–1 mol–1 .

Answer 1

Step-by-step explanation:

Hello,

In this case, starting by the ideal gas constant as shown below:

`R=8.314(J)/(mol*K)`

In order to get the requested value, the following conversion should be applied:

`R=8.314(J)/(mol*K)*(1K)/(8.314G)=1(J)/(mol*G)`

Therefore, the obtained temperature scale implies that:

`1K=8.314G`

Best regards.

Answer 2

The value of ideal gas constant (R) in Joule is 8.314 Joule
`Kelvin^(-1)`
`mol^(-1)`. Now the given expression is 1.00 J. g
`g^(-1).mole^(-1)`. Where the g represent the temperature. Thus the abbreviated g must have the value 8.314 to satisfy the original value. Thus the temperature scale will be 1 kelvin = 8.314 g. Now 1 kelvin = -272.15°C or in terms of abbreviation of g we can write -272.15 °C = 8.314g, or, 1°C = (-)
`(8.314)/(272.15)=0.030`g. Thus the temperature scale of the g scale is 1 kelvin (K) = 8.314g and 1°C = 0.030 g.