Question

Construct the triangle dce using as coordinates of its vertices points d(−4, 0), c(0, −2), and e(5,3). Find the coordinates of intersection of side ce with the x-axis.

Answer 1

So, coordinate of intersection point = (2,0)

Step-by-step explanation:

Given a triangle DCE whose coordinate of the vertex are :

D(−4, 0), C(0, −2), and E(5,3)

We will find the equation of CE

Firstly find the slope of CE

Slope (m) =
`(y_(2) - y_(1)  )/(x_(2) - x_(1))`

m =
`(3-(-2))/(5-0)` = 1

Equation of line is :

y - y₁ = m(x - x₁)

y - (-2) = 1(x-0)

y + 2 = x equation of CE

Find the intersection point of CE and x-axis

Put y = 0 to find the x-intercept

0 + 2 = x

x = 2

So, coordinate of intersection point = (2,0)