Solution: We are given:
ACT scores follow normal distribution with

SAT scores follow normal distribution with

Now, let's find the z score corresponding to Joe's SAT score 1351.




Therefore, Joe's SAT score is 1.56 standard deviations above the mean.
Now, we have find the Joe's ACT score, which will be 1.56 standard deviations above the mean.
Therefore, we have:






Therefore, Joe's equivalent ACT score to SAT score 1351 is 28.4