Answer:
(3x+4y)²
Step-by-Step Explanation:
use square of sum: (a+b)²=a²+2ab+b².
(2x+3y+x+y)²
collect like terms
((2x+x)+(3y+y))²
simplify (2x+x)+(3y+y) to 3x + 4y
Step-by-step explanation:
let (2x + 3y) be 'a'
and (x + y) be 'b'
⠀
Then the equation will be
a² + 2ab + b²
Opening the middle term
a² + ab + ab + b²
Taking common multiple
a(a + b) +b(a + b)
(a + b)(a + b)
(a + b)²
The real equation will be
(2x + 3y + x + y)²
(3x + 4y)²
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